^{X}***

Okay since we are on the derivative laws and rules part of our lives, I decided give you all a little problem to solve. Here it is:

Okay given (plus we know) that:

d

---- n

^{x}= nx

^{n - 1}

dx

d

---- a

^{x}= a

^{x}* ln a

dx

d

---- (u*v) = u * v' + v * u'

dx

d

---- ln u = u

^{-1}* u'

dx

What is:

d

---- x

^{x}

dx

## 2 comments:

Very cool question! Did you make it up or did you see it somewhere? (It's a popular conundrum.)

SPOILER

DON'T READ THIS

I'm WARNING YOU WIZOWSKI!

OK, I WON'T RUIN IT

JUST A HINT

Requires starting by taking the natural log of both sides. ;-)

I saw it somewhere.

I tried myself but I didnt get it at first. Now I know what it is, so I wishing to pass it on to my other classmates

=D

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