SUMMARY

- Exam Review Intro
- Related Rates: Area, Perimeter, and Diagonal of a Rectangle
- Related Rates: Shadows Including Similar Triangles
- Related Rates: Distance and Velocity and Spongebob!

Exam Review Intro

We do our exam review in three ways:

- Doing mini-exams pre-test style
- Doing questions in class related to rusty topics
- Doing old exam free-response questions and study how each question evolved throughout the years and do 3 questions a night

Related Rates: Area, Perimeter, and Diagonal of a Rectangle

The length (L), the width (W), and the rates of which the lengths (dL/dt) and widths (dW/dt) are changing.

By convention, we're going to designate an increasing rate as a positive rate and a decreasing rate as a negative rate.

a) We know the formula for the area of a rectangle as A = L * W, where A is area, L is length, and W is width. Since we're looking for the rates of change (That's the definition of a derivative!) we differentiate the formula, with respect to time.

Since L * W is a product, we use The Product Rule to differentiate.

Since area, length, and width are all with respect to time--meaning that area, length, and width are functions of time--we must use The Chain Rule to differentiate.

Answer: dA/dt = 32 cm/s^2; increasing

b) We know the formula for the perimeter of a rectangle as P = 2L + 2W. Differentiate the formula using The Chain Rule, since P, L, and W are with respect to time--a function within a function! Then plug and chug.

Answer: dP/dt = -2 cm/s; decreasing

c) We know that the diagonal (D), the length (L), and the width (W) are related in The Pythagorean Theorem: the square of two sides (in this case, L and W) equals the square of the hypotenuse (D), so D^2 = L^2 + W^2. Differentiate the formula using The Power Rule and The Chain Rule.

Answer: dD/dt = -33 cm/13 s; decreasing

Related Rates: Shadows Including Similar Triangles

We know the height of the lamppost (L = 16), the height of the man (M = 6), the rate at which the man walks toward the streetlight (db/dt = -5), and the length of the man's shadow from the base of the lamppost (b = 10).

Since the man is walking toward the lamppost, by convention, the rate is negative.

b) Using similar triangles, we can see that the ratio of L to M equals the ratio of s to b+s. We simplify our proportions and differentiate to determine the rates of change (That's the definition of a derivative!). To differentiate, we use The Product Rule and The Chain Rule--Refer to Related Rates: Area, Perimeter, and Diagonal of a Rectangle for reference. We plug in the numbers to obtain ds/dt.

Answer: -3 ft/sec

a) Note this question is underlined in blue. The exam would never ask you to do part B because you need to do part B anyways to answer part A. The rate of the tip of the man's shadow is dP/dt. To obtain dP/dt, we differentiate P = b + s.

Answer: -8 ft/sec

Related Rates: Distance and Velocity and Spongebob!

HOMEWORK!

HOUSEKEEPING

- Next scribe is bench.
- Wiki constructive modification due Sunday midnight.
- Developing Expert Voices projects due soon.
- AP calculus exam is in two weeks.
- Three AP calculus exam free-response per night.
- Homework: Olympic Spongebob!
- We will be reviewing applications of derivatives (related rates and optimization), applications of integrals (density and volume), and techniques of antidifferentiating (integration by parts).

## No comments:

Post a Comment