Woo! No slides for me from today, but it's all great for I remember everything that happened today, woo! Even that weird stench (Did you guys smell that?), woo!
Okay I don't remember EVERYTHING Dr.Eviatar mentioned, (the beautiful assortment of her colorful vocabulary... are just way to colorful for me to comprehend) but I know she talked something about LOGARITHMS, woo!
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Here's what I perceived:
Def'n Logarithm : A LOGARITHM IS AN EXPONENT (this was learned in the ultimate pre calculus 40s class which overshadowed all other pre cal 40s classes, you can find the ultimate blog right here: http://pc40sf07.blogspot.com/2007/11/todays-slides-november-5.html, woo!)
or
Def'n Logarithm: The inverse of exponentiation
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Exponents interact differently with each other in different scenarios:
When exponents are being multiplied with each other, the exponents form a sum.
(b^x)(b^y) = b^(x+y)
Logarithms work the same way because A LOGARITHM IS AN EXPONENT
[log(x)][log(y)] = log(x+y)
When exponents are being divided with each other, the exponents form a difference.
(b^x) / (b^y) = b^(x-y)
Logarithms also work this way because A LOGARITHM IS AN EXPONENT
[log(x)] / [log(y)] = log(x-y)
When exponents are being exponentiated with each other, the exponents form a product.
(b^x)^y = b^(xy)
Of course Logarithms work this way too because... EVERYONE SAY IT WITH ME! Class says, "A LOgshi...m AN mnj5ENT," exactly! How many times do I have to say it? Woo!
[log(x)]^y = (y)[log(x)]
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That's everything I remember Dr.Eviatar reviewed with us, woo!
We were then told to do Exercise 1.7
This concludes my post. Till next time, Au Revoir!
- Le Joseph
(oh and I pick Not Paul! Woo! Come on down!)
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